Twist, Turn, Repeat – The Art of Rotating Arrays
Rotate & Rule – Mastering Array Rotation Today’s challenge is all about rotation — but not on the dance floor! Given an array, rotate it to the right by k steps. Sounds easy? Let's break it down and explore three different ways to solve this classic problem. The Best Data Structure for Solving It (and Why!) Since the input is a simple array and we need to modify it in-place (if possible), there's no need for complex data structures. We only need: An array ( int[] nums ) : Our main data structure. In some approaches: temporary arrays or helper variables . The most optimized solution doesn't even require extra space — just clever pointer manipulation. Different Approaches – Brute Force to Optimized Solutions 1. Brute Force (Rotate One Step at a Time) This method rotates the array by shifting every element one position to the right, and doing it k times. class Solution { public void rotate ( int [] nums, int k) { int n = nums.length; ...